8x^2-35=-18x

Solution for 8x^2-35=-18x equation:

8x^2-35=-18x

We move all terms to the left:

8x^2-35-(-18x)=0

We get rid of parentheses

8x^2+18x-35=0

a = 8; b = 18; c = -35;
Δ = b2-4ac
Δ = 182-4·8·(-35)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-38}{2*8}=\frac{-56}{16}
=-3+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+38}{2*8}=\frac{20}{16}
=1+1/4
$